The well-ordering principle

July 9th, 2009 at 9:25 am

The well-ordering principle states:

The well-ordering principle: Any nonempty set of nonnegative integers has a smallest element.

DUH, you don’t say! – seems obvious, doesn’t it? This principle is, nevertheless, a very important and fundamental tool for proving other basic principles of number theory.

Consider, for instance, the Division Algorithm:

The Division Algorithm: If m and n are integers with n > 0, then there exist integers q and r, with 0 <= r < n, such that m = qn + r.

Again, this is so basic that one may doubt whether it should even be proved. But the well-ordering principle allows us, in fact, to prove the division algorithm in a rigorous manner:

Let W=\{m-tn|t\in \mathbb{Z}\}. It is obvious that W contains nonnegative integers. Let V=\{v\in W|v \geq0\}. By the well-ordering principle, V has a smallest element, which we’ll call r. r\in V, so r = m-qn for some q and r >= 0 (by the definition of sets W and V, correspondingly).

Now, what’s left to prove is that r < n. Let’s assume the opposite, namely that r=m-qn\geq n. Rearranging: r-n=m-(q+1)n\geq 0. By the definition of V, m-(q+1)n\in V (since it has the form m-tn for some integer t and is nonnegative). But recall that we called r the smallest element of V, and m-(q+1)n\le r, so we have a contradiction.

Therefore, we see that r < n. This completes the proof. Q.E.D.

Related posts:

  1. The GCD and linear combinations
  2. Equivalence classes and group partitions
  3. A group-theoretic proof of Euler’s theorem
  4. mathematical musing

4 Responses to “The well-ordering principle”

  1. ripper234No Gravatar Says:

    Have you read about the connection with the Axiom of Choice?

    I find it mind-boggling.

  2. elibenNo Gravatar Says:

    Ron, to be completely honest, I don’t think I have a good enough understanding of the philosophical foundations of mathematics to appreciate the “mind-boggling”-ness of this connection. Perhaps you can explain it to me some time.

  3. ripper234No Gravatar Says:

    For starters, read the entry on Banach-Tarski Paradox.

  4. MarkNo Gravatar Says:

    You might consider why ‘it is obvious’ that W contains nonnegative integers. In fact, proving this when m is negative requires a second application of the well-ordering principle!

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